Advertisements
Advertisements
प्रश्न
If n is a positive integer and r is a non-negative integer, prove that the coefficients of xr and xn−r in the expansion of (1 + x)n are equal
Advertisements
उत्तर
Given (1 + x)n.
General term tr+1 = nCr xn–r . ar
∴ The general term in the expansion of (1 + x)n is
Tr+1 = nCr . (1)n– r . xr
Tr+1 = nCr . xr ......(1)
∴ Coefficient of xr is nCr,
Put r = n – r in (1)
Tn–r+1 = nCn–r . xn–r
∴ The coefficient of xn-r is nCn-r ......(2)
We know nCr = nCn-r
∴ The coefficient of xr and coefficient of xn-r are equal, (by (1) and (2))
APPEARS IN
संबंधित प्रश्न
Evaluate the following using binomial theorem:
(101)4
Evaluate the following using binomial theorem:
(999)5
Find the term independent of x in the expansion of
`(2x^2 + 1/x)^12`
Show that the middle term in the expansion of is (1 + x)2n is `(1*3*5...(2n - 1)2^nx^n)/(n!)`
Find the Co-efficient of x11 in the expansion of `(x + 2/x^2)^17`
The middle term in the expansion of `(x + 1/x)^10` is
The constant term in the expansion of `(x + 2/x)^6` is
Expand `(2x^2 - 3/x)^3`
Using binomial theorem, indicate which of the following two number is larger: `(1.01)^(1000000)`, 10
Find the coefficient of x15 in `(x^2 + 1/x^3)^10`
Find the coefficient of x2 and the coefficient of x6 in `(x^2 -1/x^3)^6`
Find the last two digits of the number 3600
If n is an odd positive integer, prove that the coefficients of the middle terms in the expansion of (x + y)n are equal
In the binomial expansion of (a + b)n, if the coefficients of the 4th and 13th terms are equal then, find n
In the binomial expansion of (1 + x)n, the coefficients of the 5th, 6th and 7th terms are in AP. Find all values of n
Prove that `"C"_0^2 + "C"_1^2 + "C"_2^2 + ... + "C"_"n"^2 = (2"n"!)/("n"!)^2`
Choose the correct alternative:
The remainder when 3815 is divided by 13 is
