Advertisements
Advertisements
Question
The medians QM and RN of ΔPQR intersect at O. Prove that: area of ΔROQ = area of quadrilateral PMON.
Advertisements
Solution

Join MN. Since the line segment joining the mid-points of two sides of a triangle is parallel to the third side; so, MN || QR
Clearly, ΔQMN and ΔRNM are on the same base MN and between the same parallel lines.
Therefore, area(ΔQMN) = area(ΔRNM)
⇒ Area(ΔQMN) - area(ΔONM) = area(ΔRNM) - area(ΔONM)
⇒ Area)ΔQON) = area (ΔROM) ......(i)
We know that a median of a triangle divides it into two triangles of equal areas.
Therefore, area(ΔQMR) = area(ΔPQM)
⇒ area(ΔROQ) + area(ΔROM) = area(quad, PMON) + area(ΔQON)
⇒ area(ΔROQ) + area(ΔROM) = area(quad. PMON) + area(ΔROM) ...(from (i))
⇒ area(ΔROQ) = area(quad. PMON).
APPEARS IN
RELATED QUESTIONS
ABCD is a parallelogram. P and Q are mid-points of AB and CD. Prove that APCQ is also a parallelogram.
ABCD is a quadrilateral P, Q, R and S are the mid-points of AB, BC, CD and AD. Prove that PQRS is a parallelogram.
Prove that the line segment joining the mid-points of the diagonals of a trapezium is parallel to each of the parallel sides, and is equal to half the difference of these sides.
In a parallelogram PQRS, M and N are the midpoints of the opposite sides PQ and RS respectively. Prove that
RN and RM trisect QS.
In a parallelogram PQRS, M and N are the midpoints of the opposite sides PQ and RS respectively. Prove that
PMRN is a parallelogram.
ABCD is a trapezium in which side AB is parallel to side DC. P is the mid-point of side AD. IF Q is a point on the Side BC such that the segment PQ is parallel to DC, prove that PQ = `(1)/(2)("AB" + "DC")`.
Prove that the diagonals of a kite intersect each other at right angles.
Prove that the diagonals of a square are equal and perpendicular to each other.
In the given figure, PQ ∥ SR ∥ MN, PS ∥ QM and SM ∥ PN. Prove that: ar. (SMNT) = ar. (PQRS).
In the figure, ABCD is a parallelogram and CP is parallel to DB. Prove that: Area of OBPC = `(3)/(4)"area of ABCD"`
