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Question
The measure of x is ______.

Options
\(15 \sqrt{3} \mathrm{~cm}\)
15 cm
\(5 \sqrt{3} \mathrm{~cm}\)
5 cm
MCQ
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Solution
The measure of x is \(\underline{\boldsymbol{5 \sqrt{3} \mathrm{~cm}}}\).
Explanation:
We know that,
\[\tan \theta = \frac{\text{Perpendicular}}{\text{Base}}\]
From figure,

In \[\triangle ABC,\]
\[\Rightarrow \tan 60^\circ = \frac{AB}{BC}\]
\[\Rightarrow \sqrt{3} = \frac{15}{x}\]
\[\Rightarrow x = \frac{15}{\sqrt{3}}\]
Rationalizing the denominator,
\[\Rightarrow x = \frac{15}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}}\]
\[\Rightarrow x = \frac{15\sqrt{3}}{3}\]
\[\Rightarrow x = 5\sqrt{3}.\]
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