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The measure of x is ______.

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Question

The measure of x is ______.

The image displays a right-angled triangle with a right angle, an acute angle of $60^{\circ}$, a base of length $x\text{ cm}$, and a perpendicular height of $15\text{ cm}$.

Options

  • \(15 \sqrt{3} \mathrm{~cm}\)

  • 15 cm

  • \(5 \sqrt{3} \mathrm{~cm}\)

  • 5 cm

MCQ
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Solution

The measure of x is \(\underline{\boldsymbol{5 \sqrt{3} \mathrm{~cm}}}\). 

Explanation: 

We know that,

\[\tan \theta = \frac{\text{Perpendicular}}{\text{Base}}\]

From figure,

In \[\triangle ABC,\]

\[\Rightarrow \tan 60^\circ = \frac{AB}{BC}\]

\[\Rightarrow \sqrt{3} = \frac{15}{x}\]

\[\Rightarrow x = \frac{15}{\sqrt{3}}\]

Rationalizing the denominator,

\[\Rightarrow x = \frac{15}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}}\]

\[\Rightarrow x = \frac{15\sqrt{3}}{3}\]

\[\Rightarrow x = 5\sqrt{3}.\]

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Chapter 22: Height and Distances - EXERCISE 22 (A) [Page 346]

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Selina Concise Mathematics [English] Class 10 ICSE
Chapter 22 Height and Distances
EXERCISE 22 (A) | Q 1. (a) | Page 346
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