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The mean of the following distribution is 50. Find the unknown frequency: Class 0 – 20 20 – 40 40 – 60 60 – 80 80 – 100 Frequency 6 f 8 12 8 - Mathematics

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Question

The mean of the following distribution is 50. Find the unknown frequency:

Class 0 – 20 20 – 40 40 – 60 60 – 80 80 – 100
Frequency 6 f 8 12 8
Sum
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Solution

Step 1: Set up the calculation table

First, we need to find the class mark (xi) for each interval, which is the midpoint of the class. Then, we calculate the product of the frequency (fi) and the class mark (xi).

Class Frequency (fi) Class Mark (xi) fi × xi
0 – 20 6 10 60
20 – 40 f 30 30f
40 – 60 8 50 400
60 – 80 12 70 840
80 – 100 8 90 720
Total Σfi = 34 + f   Σfixi = 2020 + 30f
Step 2: Apply the mean formula

The formula for the mean `(barx)` is:

`barx = (sumf_ix_i)/(sumf_i)`

Given that the mean `(barx) = 50`, we can substitute the values from our table into the equation:

`50 = (2020 + 30f)/(34 + f)`

Step 3: Solve for f

1. Multiply both sides by (34 + f):

50(34 + f) = 2020 + 30f

2. Expand the left side:

1700 + 50f = 2020 + 30f

3. Rearrange the terms to group the f variables on one side:

50f – 30f = 2020 – 1700

20f = 320

4. Divide by 20:

f = `320/20`

f = 16

The unknown frequency f is 16.

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Chapter 21: Measures of central tendency - Exercise 21A [Page 462]

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Nootan Mathematics [English] Class 10 ICSE
Chapter 21 Measures of central tendency
Exercise 21A | Q 15. | Page 462
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