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प्रश्न
The mean of the following distribution is 50. Find the unknown frequency:
| Class | 0 – 20 | 20 – 40 | 40 – 60 | 60 – 80 | 80 – 100 |
| Frequency | 6 | f | 8 | 12 | 8 |
बेरीज
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उत्तर
Step 1: Set up the calculation table
First, we need to find the class mark (xi) for each interval, which is the midpoint of the class. Then, we calculate the product of the frequency (fi) and the class mark (xi).
| Class | Frequency (fi) | Class Mark (xi) | fi × xi |
| 0 – 20 | 6 | 10 | 60 |
| 20 – 40 | f | 30 | 30f |
| 40 – 60 | 8 | 50 | 400 |
| 60 – 80 | 12 | 70 | 840 |
| 80 – 100 | 8 | 90 | 720 |
| Total | Σfi = 34 + f | Σfixi = 2020 + 30f |
Step 2: Apply the mean formula
The formula for the mean `(barx)` is:
`barx = (sumf_ix_i)/(sumf_i)`
Given that the mean `(barx) = 50`, we can substitute the values from our table into the equation:
`50 = (2020 + 30f)/(34 + f)`
Step 3: Solve for f
1. Multiply both sides by (34 + f):
50(34 + f) = 2020 + 30f
2. Expand the left side:
1700 + 50f = 2020 + 30f
3. Rearrange the terms to group the f variables on one side:
50f – 30f = 2020 – 1700
20f = 320
4. Divide by 20:
f = `320/20`
f = 16
The unknown frequency f is 16.
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