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प्रश्न
Calculate the mean of the following frequency distribution:
| Class interval | 5 – 15 | 15 – 25 | 25 – 35 | 35 – 45 | 45 – 55 |
| Frequency | 2 | 6 | 4 | 8 | 4 |
बेरीज
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उत्तर
Step 1: Find the class marks (xi)
The class mark is the midpoint of each interval, calculated as:
Class Mark (xi) = `("Lower Limit" + "Upper Limit")/2`
Step 2: Create a calculation table
We multiply each frequency (fi) by its corresponding class mark (xi) to get fixi.
| Class Interval | Frequency (fi) | Class Mark (xi) | fi × xi |
| 5 – 15 | 2 | 10 | 20 |
| 15 – 25 | 6 | 20 | 120 |
| 25 – 35 | 4 | 30 | 120 |
| 35 – 45 | 8 | 40 | 320 |
| 45 – 55 | 4 | 50 | 200 |
| Total | Σfi = 24 | Σfixi = 780 |
Step 3: Apply the mean formula
The formula for the mean `(barx)` is:
`barx = (sumf_ix_i)/(sumf_i)`
Substituting the values from our table:
`barx = 780/24`
`barx = 32.5`
The mean of the given frequency distribution is 32.5.
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