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Question
The mean of 9 variates is 11. If eight of them are 7, 12, 9, 14, 21, 3, 8 and 15, find the 9th variate.
Sum
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Solution
Given: Mean of 9 variates = 11; eight variates are 7, 12, 9, 14, 21, 3, 8 and 15.
Step-wise calculation:
1. Total sum of 9 variates
= Mean × Number
= 11 × 9
= 99
2. Sum of the eight given variates
= 7 + 12 + 9 + 14 + 21 + 3 + 8 + 15
= 89
3. Ninth variate
= Total sum – Sum of eight
= 99 – 89
= 10
The 9th variate is 10.
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