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Question
The line segment joining A (2, 3) and B (6, – 5) is intersected by the X axis at the point K. Write the ordinate of the point K. Hence find the ratio in which K divides AB.
Sum
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Solution
A (2, 3) and B (6,- 5)
Intersected at X axis at K.
∴ y = 0 or ordinate = 0
K (x, 0)
Let required ratio be a: 1
∴ Ordinate of K = 0
0 = `(a xx -5 + 1 xx 3)/(a + 1)`
0 = -5a + 3
5a = 3, a = `(3)/(5)`
∴ K divides AB in ratio of 3 : 5.
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Co-ordinates Expressed as (x,y)
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