Question

The line `(3x)/5 - (2y)/3 + 1 = 0` contains the point (m, 2m – 1); calculate the value of m.

Answer 1

The equation of the given line is `(3x)/5 - (2y)/3 + 1 = 0`

Putting x = m, y = 2m − 1, we have:

`(3m)/5 - (2(2m - 1))/3 + 1 = 0`

`(3m)/5 - (4m - 2)/3 + 1 = 0`

`(9m - 20m + 10)/15 = -1`

9m – 20m + 10 = –15

–11m = –25

`m = 25/11 = 2 3/11`