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The length, width and height of a rectangular solid are in the ratio of 3 : 2 : 1. If the volume of the box is 48cm3, the total surface area of the box is

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Question

The length, width and height of a rectangular solid are in the ratio of 3 : 2 : 1. If the volume of the box is 48cm3, the total surface area of the box is

Options

  •  27 cm2

  •  32 cm2

  • 44 cm2

  • 88 cm2

MCQ
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Solution

Length (l), width (b) and height (h) of the rectangular solid are in the ratio 3 : 2 : 1.

So we can take,

(l) = 3x cm 

(b) = 2 x cm 

(h) = x cm 

We need to find the total surface area of the box

Volume of the box,

           `V= 48 cm^3`

          lbh = 48

(3x)(2x)x = 48

         6x3 = 48

           x= 8

           x = 2

Thus,

Surface area of the box,

= 2 (lb+bh+hl)

= 2 [(3x)(2x)+(2x) x +(x)(3x)]

= 2 (11x2)

= 22 x2

= 22 (2)^2

= 88 cm

Thus total surface area of the box is  88 cm.

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Chapter 18: Surface Areas and Volume of a Cuboid and Cube - Exercise 18.3 [Page 35]

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R.D. Sharma Mathematics [English] Class 9
Chapter 18 Surface Areas and Volume of a Cuboid and Cube
Exercise 18.3 | Q 6.2 | Page 35

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