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Question
The length of the shadow of a tower standing on level ground is found to be 2x metres longer when the sun's elevation is 30° than when it was 45°. The height of the tower is ______.
Options
`(2sqrt(3)x)` m
`(3sqrt(2)x)` m
`(sqrt(3) - 1)x` m
`(sqrt(3) + 1)x` m
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Solution
The length of the shadow of a tower standing on level ground is found to be 2x metres longer when the sun's elevation is 30° than when it was 45°. The height of the tower is `underlinebb((sqrt(3) + 1)x m)`.
Explanation:

Let h m be the height of the tower and let a m and (a + 2x) m be the lengths of the shadows of the tower when sun’s elevation is 45° and 30° respectively.
Then, `h/a = tan 45^circ = 1`
⇒ a = h
`h/(a + 2x) = tan 30^circ = 1/sqrt(3)`
⇒ `h/(h + 2x) = 1/sqrt(3)`
∴ `sqrt(3)h = h + 2x`
⇒ `2x = (sqrt(3) - 1)h`
⇒ `h = (2x)/((sqrt(3) - 1))`
∴ `h = {(2x)/((sqrt(3) - 1)) xx ((sqrt(3) + 1))/((sqrt(3) + 1))}`
= `x(sqrt(3) + 1)`
