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Question
The LCM of two numbers is 210 and their HCF is 14. How many such pairs are possible?
Sum
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Solution
Product of two numbers = LCM × HCF
x × y = 210 × 14
x × y = 2940
(12, 245), (20, 147)
Two pairs possible.
| 2 | 2940 |
| 2 | 1470 |
| 5 | 735 |
| 7 | 147 |
| 7 | 21 |
| 3 |
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Relationship between the Numbers and their HCF and LCM
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