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Question
The integral form of Gauss's Law is given by:
Options
\[\oint\vec{E}\cdot d\vec{S}=Q_{enc}\]
\[\oint\vec{E}\cdot d\vec{S}=\frac{Q_{enc}}{\varepsilon_0}\]
\[\Phi_E = Q_{enc} \times \varepsilon_0\]
\[E = \frac{Q_{enc}}{4\pi\varepsilon_0}\]
MCQ
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Solution
The integral form of Gauss's Law uses the closed surface integral notation (∮) to express that the dot product of the electric field and the area element, integrated over the entire closed surface, equals the enclosed charge divided by ε₀. This form is particularly useful in calculations.
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