Advertisements
Advertisements
Question
The horizontal speed of the wave is:
Options
$$ 1 \mathrm{~ms}^{-1}$$
$$ 2 \mathrm{~ms}^{-1}$$
$$ 4 \mathrm{~ms}^{-1}$$
$$ 0.5 \mathrm{~ms}^{-1}$$
MCQ
Advertisements
Solution
$$ \mathbf2 \mathbf{~ms}^{-1}$$
Explanation:
The wavelength of the wave is 4 m and its time period is 2 s.
\[ v=\frac{\lambda}{T} \]
\[=\frac{4}{2}\]
= $$ 2 \mathrm{~ms}^{-1}$$
shaalaa.com
Is there an error in this question or solution?
