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The general solution of the differential equation of the type dxdy+p1y=θ1 is -

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Question

The general solution of the differential equation of the type `(dx)/(dy) + p_1y = theta_1` is

Options

  • `ye^(int p_1dy) = int (theta_1 e^(intp_1dy)) dy + c`

  • `ye^(int p_1dy) = int (theta_1 e^(intp_1dy))  + dx + c`

  • `xe^(int p_1dy) = int (theta_1 e^(intp_1dy)) dy + c`

  • `xe^(int p_1dy) = int (theta_1 e^(intp_1dx)) dx + c`

MCQ

Solution

`xe^(int p_1dy) = int (theta_1 e^(intp_1dy)) dy + c`

Explanation:

The linear differential equation

Where P1 and θ1 are the functions of `y`.

∴ I.F. = `e^(int p_1dy)`

Hence, the solution is `x * e^(int p_1dy) = int (theta_1 e^(intp_1dy)) dy + c`.

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