English

The Function F (X) = X − [X], Where [⋅] Denotes the Greatest Integer Function is (A) Continuous Everywhere (B) Continuous at Integer Points Only

Advertisements
Advertisements

Question

The function f (x) = x − [x], where [⋅] denotes the greatest integer function is

Options

  • continuous everywhere

  • continuous at integer points only

  • continuous at non-integer points only

  • differentiable everywhere

MCQ
Answer in Brief
Advertisements

Solution

(c) continuous at non-integer points only 

\[\text{ We have }, \]
\[f\left( x \right) = x - \left[ x \right]\]
\[\text{Consider n be an integer} . \]

`f(x) = x - [x] = {(x-(n-1),n-1le x <n),(0, x = n),(x-n , n le x < n +1):}`
Now,
\[\left( \text { LHL at x = n } \right) = \lim_{x \to n^-} f\left( x \right) = x - \left( n - 1 \right) = x - n + 1\]
\[\left( \text { RHL at x } = n \right) = \lim_{x \to n^+} f\left( x \right) = x - \left( n \right) = x - n\]
\[\text { As, LHL } \neq\text {  RHL at x } = n\]
\[i . e . , \text{given function is not continuous at n} . \]
\[\text{Now, n is any integer} . \]
\[\text{Therefore, given function is not continuous at integers} . \]

Therefore, given points are continuous at non-integer points only.

 
shaalaa.com
  Is there an error in this question or solution?
Chapter 9: Differentiability - Exercise 10.4 [Page 18]

APPEARS IN

R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 9 Differentiability
Exercise 10.4 | Q 14 | Page 18

RELATED QUESTIONS

Discuss the continuity of the cosine, cosecant, secant and cotangent functions.


Find the value of k so that the function f is continuous at the indicated point.

f(x) = `{((kcosx)/(pi-2x)", if"  x != pi/2),(3", if"  x = pi/2):}` at x = `"pi/2`


Find the value of k so that the function f is continuous at the indicated point.

f(x) = `{(kx +1", if"  x<= pi),(cos x", if"  x > pi):}` at x = π


Let  \[f\left( x \right) = \frac{\log\left( 1 + \frac{x}{a} \right) - \log\left( 1 - \frac{x}{b} \right)}{x}\] x ≠ 0. Find the value of f at x = 0 so that f becomes continuous at x = 0.

 


Find the points of discontinuity, if any, of the following functions: 

\[f\left( x \right) = \begin{cases}x^3 - x^2 + 2x - 2, & \text{ if }x \neq 1 \\ 4 , & \text{ if } x = 1\end{cases}\]

 


Find the points of discontinuity, if any, of the following functions: \[f\left( x \right) = \begin{cases}\frac{x^4 - 16}{x - 2}, & \text{ if } x \neq 2 \\ 16 , & \text{ if }  x = 2\end{cases}\]


Find the points of discontinuity, if any, of the following functions:  \[f\left( x \right) = \begin{cases}\frac{\sin x}{x} + \cos x, & \text{ if } x \neq 0 \\ 5 , & \text { if }  x = 0\end{cases}\]


If \[f\left( x \right) = \frac{\tan\left( \frac{\pi}{4} - x \right)}{\cot 2x}\]

for x ≠ π/4, find the value which can be assigned to f(x) at x = π/4 so that the function f(x) becomes continuous every where in [0, π/2].


Discuss the continuity of f(x) = sin | x |.


Discuss the continuity of the following functions:
(i) f(x) = sin x + cos x
(ii) f(x) = sin x − cos x
(iii) f(x) = sin x cos x


Show that f (x) = cos x2 is a continuous function.


Show that f (x) = | cos x | is a continuous function.

 

If the function   \[f\left( x \right) = \frac{\sin 10x}{x}, x \neq 0\] is continuous at x = 0, find f (0).

 


If \[f\left( x \right) = \begin{cases}\frac{\sin^{- 1} x}{x}, & x \neq 0 \\ k , & x = 0\end{cases}\]is continuous at x = 0, write the value of k.


Determine the value of the constant 'k' so that function f 

\[\left( x \right) = \begin{cases}\frac{kx}{\left| x \right|}, &\text{ if }  x < 0 \\ 3 , & \text{ if } x \geq 0\end{cases}\]  is continuous at x  = 0  . 

 then f (x) is continuous for all
\[f\left( x \right) = \begin{cases}\frac{\left| x^2 - x \right|}{x^2 - x}, & x \neq 0, 1 \\ 1 , & x = 0 \\ - 1 , & x = 1\end{cases}\]  then f (x) is continuous for all

If \[f\left( x \right) = \begin{cases}\frac{1 - \sin x}{\left( \pi - 2x \right)^2} . \frac{\log \sin x}{\log\left( 1 + \pi^2 - 4\pi x + 4 x^2 \right)}, & x \neq \frac{\pi}{2} \\ k , & x = \frac{\pi}{2}\end{cases}\]is continuous at x = π/2, then k =

 


If  \[f\left( x \right) = \begin{cases}\frac{\log\left( 1 + ax \right) - \log\left( 1 - bx \right)}{x}, & x \neq 0 \\ k , & x = 0\end{cases}\] and f (x) is continuous at x = 0, then the value of k is


If the function f (x) defined by  \[f\left( x \right) = \begin{cases}\frac{\log \left( 1 + 3x \right) - \log \left( 1 - 2x \right)}{x}, & x \neq 0 \\ k , & x = 0\end{cases}\] is continuous at x = 0, then k =

 


Find the values of a and b so that the function

\[f\left( x \right)\begin{cases}x^2 + 3x + a, & \text { if } x \leq 1 \\ bx + 2 , &\text {  if } x > 1\end{cases}\] is differentiable at each x ∈ R.

If f is defined by  \[f\left( x \right) = x^2 - 4x + 7\] , show that \[f'\left( 5 \right) = 2f'\left( \frac{7}{2} \right)\] 


The function f (x) = |cos x| is


If \[f\left( x \right) = a\left| \sin x \right| + b e^\left| x \right| + c \left| x \right|^3\] 


If f(x) = 2x and g(x) = `x^2/2 + 1`, then which of the following can be a discontinuous function ______.


The function f(x) = `(4 - x^2)/(4x - x^3)` is ______.


Let f(x) = |sin x|. Then ______.


`lim_("x"-> pi) (1 + "cos"^2 "x")/("x" - pi)^2` is equal to ____________.


The value of f(0) for the function `f(x) = 1/x[log(1 + x) - log(1 - x)]` to be continuous at x = 0 should be


If `f(x) = {{:(-x^2",", "when"  x ≤ 0),(5x - 4",", "when"  0 < x ≤ 1),(4x^2 - 3x",", "when"  1 < x < 2),(3x + 4",", "when"  x ≥ 2):}`, then


The function f(x) = x2 – sin x + 5 is continuous at x =


Which concept is fundamental in determining continuity of a function at a point?


If \[f\] and \[g\] are continuous at \[x=c\], which collection is continuous at \[x=c\]?


For \[\frac{f}{g}\] to be continuous at \[x=c\], which condition is required?


At which values is \[\tan x=\dfrac{\sin x}{\cos x}\] not continuous?


If \[f\] is continuous, which scalar multiple is continuous?


What is the definition of the composite function \[f\circ g\]?


Why is \[f(x)=|1-x+|x||\] continuous for every real \[x\]?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×