Question

The following reaction is feasible or not feasible and why?

\[\ce{Cl2 + 2NaF -> 2NaCl + F2}\]

Answer 1

Feasibility depends on standard electrode potentials (reduction potentials). Fluorine (F₂) has a higher reduction potential than chlorine (Cl₂). Since (F₂) is a stronger oxidising agent, it will not be oxidised by (Cl₂). 

The EMF of the cell is:

\[\ce{E{^{\circ}_{cell}} = E{^{\circ}_{cathode}} - E{^{\circ}_{anode}}}\]

It gives a negative value. Negative cell potential means the reaction is non-spontaneous. Hence, (Cl₂) cannot oxidise (F⁻) to (F₂), so the reaction is not feasible.