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Question
The following is the p.d.f. of a r.v. X.
f(x) = `{(x/(8), "for" 0 < x < 4),(0, "otherwise."):}`
Find P(1 < x < 2)
Sum
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Solution
P(1 < X < 2) = `int_1^2 f(x).dx`
= `int_1^2 x/(8).dx`
= `(1)/(8) int_1^2x.dx`
= `(1)/(16)[x^2]_1^2`
= `(1)/(16)[4 - 1]`
= `(3)/(16)`
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Probability Distribution of a Continuous Random Variable
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