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Question
The floor of a building consists of 3000 tiles, which are rhombus shaped, and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor if the cost per m2 is ₹ 4.
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Solution
Length of first diagonal = 45cm
Length of second diagonal = 30 cm
Then area of one tile = `1/2` × first diagonal × second diagonal = 12 × 45 × 30
= 675cm2
Thus, the area of 3000 tiles = 675 × 3000
= 2025000 cm2
Hence, polishing expense = `2025000/10000`
= 202.50m2
Since 1m2 = 10000 cm2
Given polishing cost of 1m2 = Rs 4
Then the cost of polishing is 202.50 m2
= 4 × 202.50
= Rs 810
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