Advertisements
Advertisements
Question
The floor of a building consists of 3000 tiles, which are rhombus shaped, and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor if the cost per m2 is ₹ 4.
Advertisements
Solution
Length of first diagonal = 45cm
Length of second diagonal = 30 cm
Then area of one tile = `1/2` × first diagonal × second diagonal = 12 × 45 × 30
= 675cm2
Thus, the area of 3000 tiles = 675 × 3000
= 2025000 cm2
Hence, polishing expense = `2025000/10000`
= 202.50m2
Since 1m2 = 10000 cm2
Given polishing cost of 1m2 = Rs 4
Then the cost of polishing is 202.50 m2
= 4 × 202.50
= Rs 810
APPEARS IN
RELATED QUESTIONS
The diagonals of a rhombus are 7.5 cm and 12 cm. Find its area.
There is a pentagonal shaped park as shown in the figure. For finding its area Jyoti and Kavita divided it in two different ways.
Find the area of this park using both ways. Can you suggest some other way of finding its area?
A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 m2?
The area of a rhombus is 240 cm2 and one of the diagonal is 16 cm. Find another diagonal.
The diagonals of a rhombus are 7.5 cm and 12 cm. Find its area.
Find the area of a rhombus whose side is 6 cm and whose altitude is 4 cm. If one of its diagonals is 8 cm long, find the length of the other diagonal.
Find the area of the field in the form of a rhombus, if the length of each side be 14 cm and the altitude be 16 cm.
A garden is in the form of a rhombus whose side is 30 metres and the corresponding altitude is 16 m. Find the cost of levelling the garden at the rate of Rs 2 per m2.
Polygon ABCDE is divided in different parts as shown in figure. If AD = 8 cm, AH = 6 cm, AG = 4 cm, AF = 3 cm and BF = 2 cm, CH = 3cm, EG = 2.5 cm. Then find the area of the polygon.
A regular hexagon is inscribed in a circle of radius r. The perimeter of the regular hexagon is ______.
