Advertisements
Advertisements
Question
The factors of x3 −x2y − xy2 + y3 are
Options
(x + y) (x2 − xy + y2)
(x + y) (x2 + xy + y2)
(x + y)2 (x − y)
(x − y)2 (x + y)
Advertisements
Solution
The given expression to be factorized is
x3 −x2y − xy2 + y3
Take common `x^2` from the first two terms and `-y^2` from the last two terms. That is
x3 −x2y − xy2 + y3 ` = x^2 (x-y) - y^2 (x-y)`
Finally, take common (x-y)from the two terms. That is
x3 −x2y − xy2 + y3 = `(x-y)(x^2 - y^2)`
` = (x-y){(x)^2 - (y)^2 }`
` = (x- y)(x+y)(x-y)`
` = (x-y)^2 (x+y)`
APPEARS IN
RELATED QUESTIONS
Factorize a2 + 2ab + b2 - c2
Factorize x4 + x2 y2 + y4
Factorize x3 + 8y3 + 6x2 y +12xy2
If a2 + b2 + c2 = 20 and a + b + c = 0, find ab + bc + ca.
Evaluate: (4m - 2)(m2 + 5m - 6)
Multiply: (2x + 3y)(2x + 3y)
Divide: 2m3n5 by - mn
Write the coefficient of x2 and x in the following polynomials
`x^2 - 7/2 x + 8`
The variable in the expression 16x – 7 is __________
Shashi used addition to solve a word problem about the weekly cost of commuting by toll tax for ₹ 15 each day. Ravi solved the same problem by multiplying. They both got the correct answer. How is this possible?
