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Question
The excess pressure in a soap bubble of radius R and surface tension T is:
Options
`(2"T")/"R"`
`(4"T")/"R"`
4R2T
`(4"T")/"R"^2`
MCQ
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Solution
`(4"T")/"R"`
Explanation:
Extra pressure is created since the soap bubble has two surfaces.
P = `(2 xx 2"T")/"R"`
= `(4"T")/"R"`
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