Question

The excess pressure in a soap bubble of radius R and surface tension T is: 

पर्याय

• `(2"T")/"R"`

• `(4"T")/"R"`

• 4R²T

• `(4"T")/"R"^2`

Answer 1

`(4"T")/"R"`

Explanation:

Extra pressure is created since the soap bubble has two surfaces. 

P = `(2 xx 2"T")/"R"`

= `(4"T")/"R"`