Question

The electronic configuration of \[\ce{Cu(II)}\] is 3d⁹ whereas that of \[\ce{Cu(I)}\] is 3d¹⁰. Which of the following is correct?

Options

• \[\ce{Cu(II)}\] is more stable

• \[\ce{Cu(II)}\] is less stable

• \[\ce{Cu(I)}\] and \[\ce{Cu(II)}\] are equally stable

• Stability of \[\ce{Cu(I)}\] and \[\ce{Cu(II)}\] depends on nature of copper salts

Answer 1

\[\ce{Cu(II)}\] is more stable

Explanation:

\[\ce{Cu(II)}\] is more stable due to greater effective nuclear charge of \[\ce{Cu(II)}\].