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प्रश्न
The electronic configuration of \[\ce{Cu(II)}\] is 3d9 whereas that of \[\ce{Cu(I)}\] is 3d10. Which of the following is correct?
पर्याय
\[\ce{Cu(II)}\] is more stable
\[\ce{Cu(II)}\] is less stable
\[\ce{Cu(I)}\] and \[\ce{Cu(II)}\] are equally stable
Stability of \[\ce{Cu(I)}\] and \[\ce{Cu(II)}\] depends on nature of copper salts
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उत्तर
\[\ce{Cu(II)}\] is more stable
Explanation:
\[\ce{Cu(II)}\] is more stable due to greater effective nuclear charge of \[\ce{Cu(II)}\].
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संबंधित प्रश्न
Explain giving reasons:
Transition metals and many of their compounds show paramagnetic behaviour.
Write down the electronic configuration of Cr3+.
Write down the electronic configuration of Cu+.
Write down the electronic configuration of Ce4+.
Write down the electronic configuration of Co2+.
What is effective atomic number of Fe (z = 26) in [Fe(CN)6]4-?
(a) 12
(b) 30
(c) 26
(d) 36
Name the elements of 3d transition series that show maximum number of oxidation states. Why does this happen?
Which transition metal of 3d series has positive E° (M2+/M) value and why?
Out of Cr3+ and Mn3+, which is a stronger oxidising agent and why?
Which among the following elements does not belong to the first transition series?
Electronic configuration of Cu3+ is ____________.
The element with electronic configuration [xe]544f145d16S2 belongs to
Electronic configuration of manganese (Z = 25) is ______
Name the element of 3d series which exhibits the largest number of oxidation states. Give reason.
Give reason for the following statements:
Scandium (Z = 21) is a transition element but Zn (Z = 30) is not.
Define transition metals.
Assertion (A) : Copper is a non-transition element.
Reason (R) : Copper has completely filled d-orbitals in its ground state.
