Advertisements
Advertisements
Question
The electron in a hydrogen atom is typically found at a distance of about 5.3 × 10−11 m from the nucleus which has a diameter of about 1.0 × 10−15 m. Assuming the hydrogen atom to be a sphere of radius 5.3 × 10−11 m, what fraction of its volume is occupied by the nucleus?
Advertisements
Solution
Volume of nucleus = `4/3 π"r"^3`
Volume of atom = `4/3 π"R"^3`
Fraction of volume occupied by the nucleus = `(4/3π"r"^3)/(4/3π"R"^3)`
= `(0.5 xx 10^-15)^3/(5.3 xx 10^-11)^3`
= 8.39
= 8.4 × 10−16
APPEARS IN
RELATED QUESTIONS
The size of the atom in Thomson’s model is ______ the atomic size in Rutherford’s model.
An alpha particle has
The ratio of minimum to maxm wavelength in ballmer series is:-
Assume that there is no repulsive force between the electrons in an atom but the force between positive and negative charges is given by Coulomb’s law as usual. Under such circumstances, calculate the ground state energy of a He-atom.
Determine the distance of the closest approach when an alpha particle of kinetic energy 3.95 MeV approaches a nucleus of Z = 79, stops and reverses its directions.
What was the approximate thickness of the thin gold foil used in the experiment?
Where did scattered alpha-particles produce scintillations?
What was used to observe the scintillations on the screen?
Why is the nucleus treated as stationary during scattering?
What is the atomic number \[Z\] of gold used in the scattering analysis?
