Question

The electric potential at a point outside a uniformly charged spherical shell of radius \[R\] and charge \[q\] \[(r \geq R)\] is:

Options

• \[V = \frac{1}{4\pi\varepsilon_0}\cdot\frac{q}{R}\]

• \[V = 0\]

• \[V = \frac{1}{4\pi\varepsilon_0}\cdot\frac{q}{r^2}\]

• \[V = \frac{1}{4\pi\varepsilon_0}\cdot\frac{q}{r}\]

Answer 1

Outside the shell \[(r \geq R)\], the potential is \[V = \frac{1}{4\pi\varepsilon_0}\cdot\frac{q}{r}\], the same expression as for a point charge \[q\] at the center. This is because the field outside is identical to that of a point charge.