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The distance of the point P(–6, 8) from the origin is ______. (a) 8 (b) 2sqrt(7) (c) 6 (d) 10

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Question

The distance of the point P(–6, 8) from the origin is ______.

Options

  • 8

  • `2sqrt(7)`

  • 6

  • 10

MCQ
Fill in the Blanks
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Solution

The distance of the point P(–6, 8) from the origin is 10.

Explanation:

Distance formula: d2 = (x2 – x1)2 + (y2 – y1)2

According to the question,

We have,

x1 = – 6, x2 = 0

y1 = 8, y2 = 0

d2 = [0 – (– 6)]2 + [0 – 8]2

d = `sqrt((0 - (-6))^2 + (0 - 8)^2`

d = `sqrt((6)^2 + (-8)^2`

d = `sqrt(36 + 64)`

d = `sqrt(100)`

d = 10

Therefore, the distance between P(–6, 8) and origin O(0, 0) is 10.

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Chapter 7: Coordinate Geometry - Exercise 7.1 [Page 78]

APPEARS IN

NCERT Exemplar Mathematics Exemplar [English] Class 10
Chapter 7 Coordinate Geometry
Exercise 7.1 | Q 3 | Page 78
R.S. Aggarwal Mathematics [English] Class 10
Chapter 6 Coordinate Geometry
MULTIPLE-CHOICE QUESTIONS (MCQ) | Q 1. | Page 348
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