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The difference between the outer and inner curved surface areas of a hollow right circular cylinder 14 cm long is 88 cm^2. If the volume of metal used in making cylinder is 176 cm^3

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Question

The difference between the outer and inner curved surface areas of a hollow right circular cylinder 14 cm long is 88 cm2. If the volume of metal used in making cylinder is 176 cm3, find the outer and inner diameters of the cylinder. (Use π = 22/7)

Sum
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Solution

Given height of a hollow cylinder = 4cm

Let internal and external radii of hollow

Cylinder be ‘r’ and R

Given that difference between inner and outer

Curved surface = 88cm2

Curved surface area of cylinder (hollow)

= 2π (R - r)h cm2

⇒ 88 = 2π(R - r)h

⇒ 88 = 2π(R - r)14

⇒ R - r = 1             ...........(1)

Volume of cylinder (hollow) = π(R2 - r2)h cm2

Given volume of a cylinder = 176cm3

⇒ π(R2 - r2)h = 176

⇒ π(R2 - r2) x 14 = 176

⇒ R2 - r2 = 4

⇒ (R + r)(R - r) = 4

⇒ R + r = 4             .................(2)

    R - r = 1

+  R + r = 4 

    2R    = 5

2R = 5 ⇒ R = 5/2 = 2.5cm

Substituting ‘R’ value in (1)

⇒ R - r = 1

⇒ 2.5 - r = 1

⇒ 2.5 - 1 = r

⇒ r = 1.5cm

∴Internal radii of hollow cylinder = 1.5cm

External radii of hollow cylinder = 2.5cm

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Chapter 14: Surface Areas and Volumes - EXERCISE 14.1 [Page 14.21]

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R.D. Sharma Mathematics [English] Class 10
Chapter 14 Surface Areas and Volumes
EXERCISE 14.1 | Q 29. | Page 14.21
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