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Question
The difference between the outer and inner curved surface areas of a hollow right circular cylinder 14 cm long is 88 cm2. If the volume of metal used in making cylinder is 176 cm3, find the outer and inner diameters of the cylinder. (Use π = 22/7)
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Solution
Given height of a hollow cylinder = 4cm
Let internal and external radii of hollow
Cylinder be ‘r’ and R
Given that difference between inner and outer
Curved surface = 88cm2
Curved surface area of cylinder (hollow)
= 2π (R - r)h cm2
⇒ 88 = 2π(R - r)h
⇒ 88 = 2π(R - r)14
⇒ R - r = 1 ...........(1)
Volume of cylinder (hollow) = π(R2 - r2)h cm2
Given volume of a cylinder = 176cm3
⇒ π(R2 - r2)h = 176
⇒ π(R2 - r2) x 14 = 176
⇒ R2 - r2 = 4
⇒ (R + r)(R - r) = 4
⇒ R + r = 4 .................(2)
R - r = 1
+ R + r = 4
2R = 5
2R = 5 ⇒ R = 5/2 = 2.5cm
Substituting ‘R’ value in (1)
⇒ R - r = 1
⇒ 2.5 - r = 1
⇒ 2.5 - 1 = r
⇒ r = 1.5cm
∴Internal radii of hollow cylinder = 1.5cm
External radii of hollow cylinder = 2.5cm
