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Question
The diameter of the circle is 52 cm and the length of one of its chord is 20 cm. Find the distance of the chord from the centre
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Solution
Length of the chord = 20 cm
AC = `20/2`
= 10 cm
In ΔOAC, OC2 = OA2 – AC2
= 262 – 102
= (26 + 10)(26 – 10)
= 36 × 16
OC = `sqrt(30 xx 16)`
= 6 × 4 cm
= 24 cm
Distance of the chord from the centre = 24 cm.
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