Advertisements
Advertisements
प्रश्न
The diameter of the circle is 52 cm and the length of one of its chord is 20 cm. Find the distance of the chord from the centre
Advertisements
उत्तर
Length of the chord = 20 cm
AC = `20/2`
= 10 cm
In ΔOAC, OC2 = OA2 – AC2
= 262 – 102
= (26 + 10)(26 – 10)
= 36 × 16
OC = `sqrt(30 xx 16)`
= 6 × 4 cm
= 24 cm
Distance of the chord from the centre = 24 cm.
APPEARS IN
संबंधित प्रश्न
Write True or False. Give reason for your answer.
Line segment joining the centre to any point on the circle is a radius of the circle.
In Fig below, PQ is tangent at point R of the circle with center O. If ∠TRQ = 30°. Find ∠PRS.
Fill in the blank
Circles having the same centre and different radii are called ...........................circles.
If the difference between the circumference and the radius of a circle is 37 cm, then using`22/7`, the circumference (in cm) of the circle is:
The perimeter (in cm) of a square circumscribing a circle of radius a cm, is
A chord of a circle of radius 14 cm subtends an angle of 120° at the centre. Find the area of the corresponding minor segment of the circle. `[User pi22/7 and sqrt3=1.73]`
Number of circles that can be drawn through three non-collinear points is
In the adjoining figure, Δ ABC is circumscribing a circle. Then, the length of BC is ______
Two chords AB and AC of a circle subtends angles equal to 90º and 150º, respectively at the centre. Find ∠BAC, if AB and AC lie on the opposite sides of the centre.
From the figure, identify a chord.
