Advertisements
Advertisements
प्रश्न
The chord of length 30 cm is drawn at the distance of 8 cm from the centre of the circle. Find the radius of the circle
Advertisements
उत्तर
Distance AC = `1/2 xx "Length of chord"`
= `1/2 xx 30`
= 15 cm
Distance from the centre = 8 cm
In ΔOAC Radius (OA) = `sqrt("AC"^2 + "OC"^2)`
= `sqrt(15^2 + 8^2)`
= `sqrt(225 + 64)`
= `sqrt(289)`
= 17
Radius of the circle = 17 cm.
APPEARS IN
संबंधित प्रश्न
Two tangents TP and TQ are drawn to a circle with centre O from an external point T. Prove that ∠PTQ = 2∠OPQ.
In Fig., if AB = AC, prove that BE = EC
In the given figure, PA and PB are the tangent segemtns to a circle with centre O. Show that he points A, O, B and P are concyclic.
In the given figure, an isosceles triangle ABC, with AB = AC, circumscribes a circle. Prove that point of contact P bisects the base BC.
If ABCD is a cyclic quadrilateral in which AD || BC (In the given figure). Prove that ∠B = ∠C.
In the given figure, AB and CD are diameters of a circle with centre O. If ∠OBD = 50°, find ∠AOC.
In a cyclic quadrilateral ABCD if AB || CD and ∠B = 70°, find the remaining angles.
The greatest chord of a circle is called its
Draw a circle of radius of 4.2 cm. Mark its center as O. Takes a point A on the circumference of the circle. Join AO and extend it till it meets point B on the circumference of the circle,
(i) Measure the length of AB.
(ii) Assign a special name to AB.
A chord is at a distance of 15 cm from the centre of the circle of radius 25 cm. The length of the chord is
