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प्रश्न
The chord of length 30 cm is drawn at the distance of 8 cm from the centre of the circle. Find the radius of the circle
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उत्तर
Distance AC = `1/2 xx "Length of chord"`
= `1/2 xx 30`
= 15 cm
Distance from the centre = 8 cm
In ΔOAC Radius (OA) = `sqrt("AC"^2 + "OC"^2)`
= `sqrt(15^2 + 8^2)`
= `sqrt(225 + 64)`
= `sqrt(289)`
= 17
Radius of the circle = 17 cm.
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संबंधित प्रश्न
In Fig. 1, QR is a common tangent to the given circles, touching externally at the point T. The tangent at T meets QR at P. If PT = 3.8 cm, then the length of QR (in cm) is :
(A) 3.8
(B) 7.6
(C) 5.7
(D) 1.9
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