Advertisements
Advertisements
प्रश्न
The diameter of the circle is 52 cm and the length of one of its chord is 20 cm. Find the distance of the chord from the centre
Advertisements
उत्तर
Length of the chord = 20 cm
AC = `20/2`
= 10 cm
In ΔOAC, OC2 = OA2 – AC2
= 262 – 102
= (26 + 10)(26 – 10)
= 36 × 16
OC = `sqrt(30 xx 16)`
= 6 × 4 cm
= 24 cm
Distance of the chord from the centre = 24 cm.
APPEARS IN
संबंधित प्रश्न
In figure OQ : PQ = 3 : 4 and perimeter of ΔPDQ = 60cm. determine PQ, QR and OP.
The point of concurrence of all angle bisectors of a triangle is called the ______.
The circle which passes through all the vertices of a triangle is called ______.
Use the figure given below to fill in the blank:
Diameter = 2 x ________
In the figure, O is the center of the circle. Line AQ is a tangent. If OP = 3, m(arc PM) = 120°, then find the length of AP.
In the figure, O is the centre of the circle, and ∠AOB = 90°, ∠ABC = 30°. Then find ∠CAB.
AB is a diameter of a circle and AC is its chord such that ∠BAC = 30°. If the tangent at C intersects AB extended at D, then BC = BD.
In the following figure, if ∠DAB = 60º, ∠ABD = 50º, then ∠ACB is equal to ______.
What is the area of a semi-circle of diameter ‘d’?
Which is the longest straight line that can be drawn inside a circle?
