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The depression in the freezing point of a sugar solution was found to be 0.402°C. Calculate the osmotic pressure of the sugar solution at 27°C. (Kf = 1.85 K kg mol−1)

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Question

The depression in the freezing point of a sugar solution was found to be 0.402°C. Calculate the osmotic pressure of the sugar solution at 27°C. (Kf = 1.85 K kg mol−1)

Numerical
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Solution

Given: R = 0.0821 L atm mol−1 K−1

T = 27°C = 300 K

Kf = 1.85 K kg mol−1

ΔTf = 0.402°C

We know that

ΔTf = Kf

`m = (Delta T_f)/K_f`

= `0.402/1.85`

= 0.2173 mol/kg

Let 1 kg of solvent = 1 L of solution, so

C = m

= 0.2173 mol/L

By using van’t Hoff equation

π = CRT

π = 0.2173 × 0.0821 × 300

π = 5.35 atm

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Chapter 1: Solutions - QUESTIONS FROM ISC EXAMINATION PAPERS [Page 130]

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Nootan Chemistry [English] Class 12 ISC
Chapter 1 Solutions
QUESTIONS FROM ISC EXAMINATION PAPERS | Q 5. (a) | Page 130
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