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प्रश्न
The depression in the freezing point of a sugar solution was found to be 0.402°C. Calculate the osmotic pressure of the sugar solution at 27°C. (Kf = 1.85 K kg mol−1)
संख्यात्मक
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उत्तर
Given: R = 0.0821 L atm mol−1 K−1
T = 27°C = 300 K
Kf = 1.85 K kg mol−1
ΔTf = 0.402°C
We know that
ΔTf = Kf m
`m = (Delta T_f)/K_f`
= `0.402/1.85`
= 0.2173 mol/kg
Let 1 kg of solvent = 1 L of solution, so
C = m
= 0.2173 mol/L
By using van’t Hoff equation
π = CRT
π = 0.2173 × 0.0821 × 300
π = 5.35 atm
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