Advertisements
Advertisements
Question
The daily maximum relative humidity (in percent) in Mumbai from May 1 to May 7, 1992 is given below: 64, 70, 65, 80, 75, 78
Find the mean.
Advertisements
Solution
Data: 64, 70, 65, 80, 75, 78
Total number of observation = n = 6
Mean = `"Sum of observations"/"Total number of observations"`
= `(64 + 70 + 65 + 80 + 75 + 78)/(6)`
= 72.
APPEARS IN
RELATED QUESTIONS
Find the median of: 25, 16, 26, 16, 32, 31, 19, 28 and 35
The heights (in cm) of the volleyball players from team A and team B were recorded as:
Team A: 180, 178, 176, 181, 190, 175, 187
Team B: 174, 175, 190, 179, 178, 185, 177
Which team had a greater average height?
Find the median of team A and team B.
The mean weight of 60 students in a class is 40 kg. The mean weight of boys is 50 kg while that of girls is 30 kg. Find the number of boys and girls in the class.
The mean of 10 numbers is 24. If one number is included, the new mean is 25. Find the included number.
Find the mean and median of all the positive factors of 72.
The mean of x, x + 2, x + 4, x + 6 and x + 8 is 11, find the mean of the first three observations.
For the set of numbers given below, find mean: 3, 0, 5, 2, 6, 2
If the mean of 7, 16, 9, 15, 16, a, 12, 8, b, 11 is 12, write a in terms of b.
The mean of 16 natural numbers is 48. Find the resulting mean, if each of the number is divided by 0.25
The mean of 200 observations is 20. It is found that the value of 180 is wrongly copied as 280. Find the actual mean.
