Question

The current in a coil changes from 8.0 A to 2.0 A in 0.6 s. If an average emf induced in the coil is 50 V, calculate the self-inductance of the coil.

Answer 1

Given: Induced emf (e) = 50 V

Change in current (∆I) = 8.0 − 2.0 

= 6.0 A

Time interval (∆t) = 0.6 s

Formula: Self-inductance (L) = `(e xx ∆t)/|∆I|`

= `(50 xx 0.6)/6.0`

= `30/0.6`

= 5.0 H