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Question
The cross-section of a canal is a trapezium in shape. If the canal is 10m wide at the top, 6m wide at the bottom and the area of cross-section is 72 sq.m, determine its depth.
Sum
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Solution
The cross-section of the canal is a trapezium
Area of a Trapezium = `(1)/(2)("a" + "b") xx "h"`,
Where a and b are the lengths of its parallel sides
Let h the perpendicular distance between them
here, a = 10, b = 6 and perpendicular distance = h
∴ Area of Trapezium
= `(1)/(2)(10 + 6) xx "h"`
= 72m2
⇒ 8h = 72
⇒ h = 9m.
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