English

The C.P. of an article is ₹ x which is sold for 152 at a profit of (x + 10)%. Find the value of x.

Advertisements
Advertisements

Question

The C.P. of an article is ₹ x which is sold for 152 at a profit of (x + 10)%. Find the value of x.

Sum
Advertisements

Solution

Given,

C.P. = ₹ x

S.P. = ₹ 152

Profit = (x + 10) %

Profit = S.P. − C.P.

= ₹ (152 − x)

As we know that Profit % = `"Profit"/"C.P." × 100`

Substituting the values, we get

⇒ `(x + 10) = ((152 - x))/x xx 100`

⇒ x(x + 10) = (152 − x) × 100

⇒ x2 + 10x = 15200 − 100x

⇒ x2 + 10x − 15200 + 100x = 0

⇒ x2 + 110x − 15200 = 0

⇒ x2 + 190x − 80x − 15200 = 0

⇒ x(x + 190) − 80(x + 190) = 0

⇒ (x + 190)(x − 80) = 0

⇒ (x + 190) = 0 or (x − 80) = 0

⇒ x = −190 or x = 80

The cost price of the article cannot be negative.

Hence, the value of C.P. = ₹ 80.

shaalaa.com
  Is there an error in this question or solution?
Chapter 6: Solving (simple) Problems (Based on Quadratic Equations) - EXERCISE 6(C) [Page 69]

APPEARS IN

Selina Concise Mathematics [English] Class 10 ICSE
Chapter 6 Solving (simple) Problems (Based on Quadratic Equations)
EXERCISE 6(C) | Q 6. | Page 69
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×