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Question
The cost of an overhaul of an engine is ₹ 10,000 The operating cost per hour is at the rate of 2x – 240 where the engine has run x km. Find out the total cost if the engine runs for 300 hours after overhaul
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Solution
Given that the overhaul cost is ₹ 10,000.
The marginal cost is 2x – 240
MC = 2x – 240
C = `int "MC" "d"x + "k"`
C = x2 – 240x + k
k is the overhaul cost
⇒ k = 10,000
So C = x2 – 240x + 10,000
When x = 300 hours, total cost is
C = (300)2 – 240(300) + 10,000
⇒ C = 90,000 – 72000 + 10,000
⇒ C = 28,000
So the total cost of the engine run for 300 hours after the overhaul is ₹ 28,000.
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