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The cost of an overhaul of an engine is ₹ 10,000 The operating cost per hour is at the rate of 2x – 240 where the engine has run x km. Find out the total cost if the engine runs for 300 hours - Business Mathematics and Statistics

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प्रश्न

The cost of an overhaul of an engine is ₹ 10,000 The operating cost per hour is at the rate of 2x – 240 where the engine has run x km. Find out the total cost if the engine runs for 300 hours after overhaul

योग
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उत्तर

Given that the overhaul cost is ₹ 10,000.

The marginal cost is 2x – 240

MC = 2x – 240

C = `int "MC"  "d"x + "k"`

C = x2 – 240x + k

k is the overhaul cost

⇒ k = 10,000

So C = x2 – 240x + 10,000

When x = 300 hours, total cost is

C = (300)2 – 240(300) + 10,000

⇒ C = 90,000 – 72000 + 10,000

⇒ C = 28,000

So the total cost of the engine run for 300 hours after the overhaul is ₹ 28,000.

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Application of Integration in Economics and Commerce
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Integral Calculus – 2 - Exercise 3.2 [पृष्ठ ७२]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 12 TN Board
अध्याय 3 Integral Calculus – 2
Exercise 3.2 | Q 1 | पृष्ठ ७२

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