Advertisements
Advertisements
प्रश्न
For the marginal revenue function MR = 6 – 3x2 – x3, Find the revenue function and demand function
Advertisements
उत्तर
MR = 6 – 3x2 – x3
Revenue function R = `int "MR" "d"x`
R = `int (6 – 3x^2 – x^3) "d"x`
R = `(6x - (3x^3)/3 - x^4/4) + "k"`
When x = 0
R = 0
⇒ k = 0
∴ R = `6 - x^3 -x^4/4`
Demand function P = `"R"/x`
= `((6x - x^3 - x^4/4))/x`
P = `6 - x^2 - x^3/4`
APPEARS IN
संबंधित प्रश्न
The cost of an overhaul of an engine is ₹ 10,000 The operating cost per hour is at the rate of 2x – 240 where the engine has run x km. Find out the total cost if the engine runs for 300 hours after overhaul
Determine the cost of producing 200 air conditioners if the marginal cost (is per unit) is C'(x) = `x^2/200 + 4`
If the marginal revenue function for a commodity is MR = 9 – 4x2. Find the demand function.
The marginal cost of production of a firm is given by C'(x) = 5 + 0.13x, the marginal revenue is given by R'(x) = 18 and the fixed cost is ₹ 120. Find the profit function
Find the revenue function and the demand function if the marginal revenue for x units is MR = 10 + 3x – x2
Choose the correct alternative:
The given demand and supply function are given by D(x) = 20 – 5x and S(x) = 4x + 8 if they are under perfect competition then the equilibrium demand is
Choose the correct alternative:
If the marginal revenue MR = 35 + 7x – 3x2, then the average revenue AR is
Choose the correct alternative:
The producer’s surplus when the supply function for a commodity is P = 3 + x and x0 = 3 is
A manufacture’s marginal revenue function is given by MR = 275 – x – 0.3x2. Find the increase in the manufactures total revenue if the production is increased from 10 to 20 units
A company requires f(x) number of hours to produce 500 units. It is represented by f(x) = 1800x–0.4. Find out the number of hours required to produce additional 400 units. [(900)0.6 = 59.22, (500)0.6 = 41.63]
