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Given the marginal revenue function 4(2x+3)2-1 show that the average revenue function is P = 46x+9-1

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प्रश्न

Given the marginal revenue function `4/(2x + 3)^2 - 1` show that the average revenue function is P = `4/(6x + 9) - 1`

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उत्तर

M.R = `4/(2x + 3)^2 - 1` 

Total Revenue R =`int"M.R"  "d"x`

R = `int (4/(2x + 3)^2 - 1)  "d"x`

= `int [4(2x + 3)^-2 - 1]  "d"x`

R = `[4[(2x + 3)^(-2 + 1)/(-2 + 1)] - x] + "k"`

R = `4[(2x + 3)^1/((-1) xx 2)] - x + "k"`

R = `4[1/(-2(2x + 3))] - x + "k"`

R = `(-2)/((2x + 3)) - x + "k"`   .......(1)

When x = 0

R = 0

⇒ 0 = `(-2)/([2(0) + 3]) - 0 + "k"`

0 = `(-2)/3 + "k"``

⇒ k = `2/3`

From eqaution (1)

⇒ R = `(-2)/((2x + 3)) - x + 2/3`

⇒ R = `2/3 - 2/((2x + 3)) - x`

R = `(2(2x + 3) - 2(3))/(3(2x + 3)) - x`

= `(4x + 6 - 6)/((6x + 9)) - x`

∴ R = `(4x)/((6x + 9)) - x`

Average Revenue A.R = `"R"/x`

= `([(4x)/((6x + 9))  x])/x`

A.R = `4/((6x + 9)) - 1`

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Application of Integration in Economics and Commerce
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Integral Calculus – 2 - Exercise 3.2 [पृष्ठ ७२]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 12 TN Board
अध्याय 3 Integral Calculus – 2
Exercise 3.2 | Q 12 | पृष्ठ ७२

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