Advertisements
Advertisements
Question
The cost of a machine depreciates by 10% every year. If its present worth is Rs.18,000; what will be its value after three years?
Advertisements
Solution
Applying the formula, we get;
Value after 3 years = ₹ 18,000`(1 - 10/100)^3`
= ₹ 13,122
RELATED QUESTIONS
Pradeep gave Rs.16000 to a friend for 1.5 years at 15% p.a. compounded semi-annually. Find the interest earned by him at the end of 1.5 years.
What sum of money will amount to Rs 7,128 in 2 years at compound interest, if the rates of interest are 8% and 10% for successive years?
What sum of money will amount to Rs 3,326.40 in 3 years at compound interest, if the rates of interest are 8%, 10% and 12% for the successive years?
The value of a machine depreciates by 15% in the first year and by 12% in the second year. Find the value of the machine if its depreciation in the second year was Rs 1,632.
The value of a 'Honda' bike depreciated by 16% in the first year and by 13% in the second year. Find the value of the bike if it depreciated by Rs 7,098 in the second year.
Rajan borrowed Rs 32,000 at 12% compound interest for 2 years. At the end of the first year he returned some amount and on paying Rs 17,920 at the end of the second year, he cleared the loan. Calculate the amount Rajan paid at the end of the first year.
The simple interest on an amount for 2 years at 8% is Rs 320. Calculate the compound interest on the same amount at the same rate for 1 year if the interest is compounded half-yearly.
Calculate the amount and the compound interest for the following:
Rs 12,500 for 3 years if the rates for the successive years are 8%, 9% and 10% respectively.
In what time will Rs 50,000 yield an interest of Rs 32,151.60 at 18% per annum interest compounded annually?
In how many years will Rs. 15,625 amount to Rs. 17,576 at 4% p.a., compound interest?
