Advertisements
Advertisements
Question
The cost of a machine depreciates by 10% every year. If its present worth is Rs.18,000; what will be its value after three years?
Advertisements
Solution
Applying the formula, we get;
Value after 3 years = ₹ 18,000`(1 - 10/100)^3`
= ₹ 13,122
RELATED QUESTIONS
Mr.Mohan invested Rs. 12500 at 16 % p.a. compounded annually. If the duration of the deposite was 1.5 years , find the amount Mr.Mohan received at the end of 1.5 years.
Rajeev borrowed Rs 15,000 from Sanjay at 12% p.a. compound interest. After 2 years Rajeev gave Rs 7,500 and a scooter to clear the account. Find the cost of the scooter.
Mr. Chatterjee borrowed Rs 50,000 in compound interest from Mr. Patel for 2 years when the rates of interest for the successive years were `7 1/2 %` and `9 1/4 %`. If Mr. Chatterjee returned Rs 27, 750 at the end of the first year, find the amount he needs to return at the end of the seoond year to clear the loan.
What sum of money will amount to Rs 16,637.50 in 3 years at 10 % p.a. compound interest?
The interests on two successive years for a sum invested at compound interest compounded annually are Rs 840 and Rs 940.80. Calculate the rate of interest and the sum invested.
The cost of a machine dep reciated by Rs 2592 during the third year and by Rs 2332.80 during the fourth year. Calculate :
The cost at the end of the fourth year.
What sum of money will amount to Rs 18, 792 in `1 1/2` years at 16% p.a. compounded yearly?
On what sum of money will the compound interest for 2 years at 10% p.a. compounded half-yearly amount to Rs 3,448.10?
The compound interest on a certain sum of money at 5% p.a. for 2 years is Rs 512.50. What will be the simple interest on the same sum for 3 years at 6% p.a.?
In how many years will Rs. 15,625 amount to Rs. 17,576 at 4% p.a., compound interest?
