Advertisements
Advertisements
प्रश्न
The cost of a machine depreciates by 10% every year. If its present worth is Rs.18,000; what will be its value after three years?
Advertisements
उत्तर
Applying the formula, we get;
Value after 3 years = ₹ 18,000`(1 - 10/100)^3`
= ₹ 13,122
संबंधित प्रश्न
The cost of a scooter depreciated by Rs 5100 during the second year and by Rs 4,335 during the third year. Calculate
The original cost of the scooter.
The cost of a machine depreciated by Rs 2592 during the third year and by Rs 2332.80 during the fourth year. Calculate :
The original cost.
Ramesh borrowed Rs 12,000 at 15% compound interest for 2 years. At the end of the first year he returned some amount and on paying Rs 9,200 at the end of the second year, he cleared the loan. Calculate the amount of money Ramesh returned at the end of the first year.
Calculate the amount and cornpound interest for the following, when cornpounded annually:
Rs 8,000 for `1 1/2` years at 12 % p.a.
Calculate the amount and cornpound interest for the following, when cornpounded annually:
Rs 7 ,500 for `2 1/2` years ; r =16 % p.a.
What sum of money will amount to Rs 8,073 in 2 years at compound interest if the rates of interest for the successive years are 15% and 17%?
Find the principal which will amount to Rs 22,344 in 2 years at compound interest if the rates of interest for the successive years are 12% and 14%?
What sum of money will amount to Rs 10,256.40 in 3 years at compound interest if the rates of interest for the successive years are 10%, 11% and 12%?
A sum of money placed at compound interest compounded annually amounts to Rs 26,460 in 2 years and to Rs 29,172.15 in 4 years. Calculate the rate of interest and the sum.
If the interest is compounded half yearly, calculate the amount when the Principal is Rs. 7,400, the rate of interest is 5% per annum and the duration is one year.
