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Question
The cost of a machine depreciated by Rs 2592 during the third year and by Rs 2332.80 during the fourth year. Calculate :
The original cost.
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Solution
Depreciation for seoond year = Rs 2,592 + 10 % of Rs 2,592
Here, 10 % of Rs 2,592 =Rs 259.20
Hence, Depreciation for seoond year
= Rs 2,592 +Rs 259.20 =Rs 2,851.20
Depreciation for first year = Rs 2,851.20 + 10 % of Rs 2,851.20
Here, 10 % of Rs 2,851.20 = Rs 285.12
Hence, Depreciation for first year
= Rs 2,851.20 + Rs 285.12 = Rs 3, 136.32
Total depreciation for 4 years
= Rs (3, 136.32 + 2,851.20 + 2,592 + 2,332.80)
=Rs 10,912.32
A= P - Rs 10,912.32 ; P = x
`"A" = "P" (1 + "r"/100)^"n"`
`"x" - 10912.32 = "x" (1 - 10/100)^4`
`"x" - 10912.32 = "x" xx 1.1 xx 1.1 xx 1.1 xx 1.1`
x (1 - 0.6561) = Rs 10912.32
`"x" = "Rs" 10912.32/0.3439`
X=RS 31731.08
⇒ x = Rs 32,000 (approx)
Original cost= Rs 32,000
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