Question

The common difference of the A.P. \[\frac{1}{2b}, \frac{1 - 6b}{2b}, \frac{1 - 12b}{2b}, . . .\] is 

 

Options

•  2b

• −2b

• 3

•  - 3 

Answer 1

Let a be the first term and d be the common difference.
The given A.P. is  \[\frac{1}{2b}, \frac{1 - 6b}{2b}, \frac{1 - 12b}{2b}, . . .\]

Common difference = d = Second term − First term
                                       = \[\frac{1 - 6b}{2b} - \frac{1}{2b}\]

                                       = \[\frac{- 6b}{2b} = - 3\]