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The circumference of a circle is 88 cm. Find the area of the sector whose central angle is 72°.

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Question

The circumference of a circle is 88 cm. Find the area of the sector whose central angle is 72°.

Sum
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Solution

Given:

Circumference C = 88 cm

Central angle θ = 72°

Step-wise calculation:

1. Circumference formula:

C = 2πr 

⇒ `r = C/(2π)` 

= `(88)/(2π)` 

= `(44)/π` cm

2. Area of a sector:

`A = (θ/360) xx πr^2`

3. Compute r2:

`r^2 = (44/π)^2` 

= `(1936)/π^2`

4. Substitute into sector area:

`A = (72/360) xx π xx (1936/π^2)` 

= `(1/5) xx π xx (1936/π^2)` 

= `(1936)/(5π) cm^2`

5. Decimal approximation:

`A ≈ (1936)/(5·3.14159265)` ≈ 123.2 cm2

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Chapter 16: Area of Circle, Sector and Segment - EXERCISE 16B [Page 748]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 16 Area of Circle, Sector and Segment
EXERCISE 16B | Q 18. | Page 748
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