Question

The centre of a circle is (−4, 2). If one end of the diameter of the circle is (−3, 7) then find the other end

Answer 1

Let the other end of the diameter B be (a, b)

Mid−point of a line = `((x_1 + x_2)/2, (y_1 + y_2)/2)(-3, 7)`

(−4, 2) = `((-3 + "a")/2, (7 + "b")/2)`

∴ `(-3 + "a")/2` = − 4

−3 + a = − 8

a = – 8 + 3

a = −5

`(7 + "b")/2`

7 + b = 4

b = 4 – 7

⇒ b = – 3

The other end of the diameter is (– 5, – 3).