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Question
The Cartesian product \(A\times A\) has \(9\) elements and contains \((-1,0)\) and \((0,1)\). What is \(A\)?
Options
\(\{-1,0,1,9\}\)
\(\{-1,0\}\)
\(\{-1,0,1\}\)
\(\{0,1\}\)
MCQ
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Solution
Since \(n(A\times A)=9\), \(n(A)^2=9\), so \(n(A)=3\). The two given ordered pairs require \(-1\), \(0\), and \(1\) to belong to \(A\).
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