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The Cartesian product \(A\times A\) has \(9\) elements and contains \((-1,0)\) and \((0,1)\). What is \(A\)?

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Question

The Cartesian product \(A\times A\) has \(9\) elements and contains \((-1,0)\) and \((0,1)\). What is \(A\)?

Options

  • \(\{-1,0,1,9\}\)

  • \(\{-1,0\}\)

  • \(\{-1,0,1\}\)

  • \(\{0,1\}\)

MCQ
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Solution

Since \(n(A\times A)=9\), \(n(A)^2=9\), so \(n(A)=3\). The two given ordered pairs require \(-1\), \(0\), and \(1\) to belong to \(A\).

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